What is the potential difference between the plates of a 4.6-F capacitor that stores sufficient energy to operate a 75.0-W light bulb for one minute?
How do i get the answer to be 44.2 V?

V = 44.2 V

Explanation:

We have time = 1 minute = 60 sec, C = 4.6 F, P = 75.0 W

Solution:

Electric Potential Energy U Formula in capacitor for the given data.

U = 1/2 CV²

V =

So to find energy U = Pt = 75.0 W × 60 sec

U = 4500 J

now V =

V = 44.232 = 44.2 V

absorption lines are where light has been absorbed by the atom thus you see a dip in the spectrum whereas.

emission spectra have spikes in the spectra due to atoms releasing photons at those wavelengths.

explanation:

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.