A mass of 0.400 is raised by a vertical distance of 0.450m in the earths growth gravitational field. what is the change in its gravitatioanal potential energy? show your work

w = 1.766 Joule

Explanation:

Work = Force × Distance

In this case the Work done is stored in body as Gravitational potential energy, so , W = P. E. = mgh

Here m = 0.400 kg ( unit not given in the question if in other unit may be converted to Kg), g = 9.81 m/s² and h= 0.450 m

w =  0.400 kg × 9.81 m/s² × 0.450 m

w = 1.7658 kg m²/s²  =  1.766 Joule  or (Nm)

Complete question: A mass of 0.400 kg is raised by a vertical distance of 0.450 m in the earth's gravitational field. What is the change in its gravitational potential energy?

1.764 J

Explanation:

Gravitational Potential Energy: This ca be defined as the energy possessed by a body due to its position in the gravitational field. The S.I unit is J.

The expression for change in Gravitational potential energy is

ΔEp = mgΔh Equation 1

Assuming the ground level = 0 m

Where ΔEp = change in Gravitational potential energy, m = mass , g = acceleration due to gravity, h = change in height.

Given: m = 0.40 kg, Δh = 0.450 m, g = 9.8 m/s²

Substitute into equation 1

ΔEp = 0.4(0.45)(9.8)

ΔEp = 1.764 J

Hence the change in gravitational potential energy = 1.764 J

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂