How far will 20 N of force stretch a spring with a spring constant of 140 N/m?

0.143 m

Explanation:

The relationship between force applied on a string and stretching of the spring is given by Hooke's law:

where

F is the force exerted on the spring

k is the spring constant of the spring

x is the stretching of the spring from its equilibrium position

In this problem, we have:

F = 20 N is the force applied on the spring

k = 140 N/m is the spring constant

Solving for x, we find how far the spring will stretch:

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