A small boat is moving at a velocity of 3.35 when it is accelerated by a river current perpendicular to the initial direction of motion. If the acceleration of the current is 0.750 m/s2, what will be the new velocity of the boat after 3.35s?

The answer is 5.86m/s

Explanation:

Acceleration is defined as the change in velocity of a body with respect to time. Mathematically,

Acceleration = change in velocity/time(t)

Change in velocity = final velocity (v)- initial velocity (u)

Acceleration = v-u/t

Given the following;

Acceleration = 0.75m/s²

Initial velocity = 3.35m/s

Time taken = 3.35s

Final velocity = v

Substituting the data given in the formula to get the final velocity we have;

0.75 = (v-3.35)/3.35

0.75×3.35 = v-3.35

2.51 = v-3.35

v = 2.51+3.35

v = 5.86m/s

Therefore the new velocity of the object will be 5.86m/s

Given Information:

Acceleration = a = 0.750 m/s²

Initial velocity = v₁ = 3.35 m/s

time = t = 3.35 seconds

Required Information:

new velocity = v₂ = ?

new velocity = 5.86 m/s

Explanation:

We know from the kinematic equations,

v = u + at

Here u = v₁ and v = v₂

v₂ = v₁ + at

v₂ = 3.35 + 0.750*3.35

v₂ = 3.35 + 2.512

v₂ = 5.86 m/s

Therefore, the new velocity of the boat after it was accelerated by a river current is 5.86 m/s.

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