Car A is traveling north on a straight highway and car B is traveling west on a different straight highway. Each car is approaching the intersection of these highways. At a certain moment, car A is 0.3 km from the intersection and traveling at 90 km/h while car B is 0.4 km from the intersection and traveling at 80 km/h. How fast is the distance between the cars changing at that moment?

Car A is 1.8-1.2= 0.6 times faster than car B

So the distance between them is changing 0.6 times faster.

Explanation:

Car A is traveling north at 90km/hr and 0.3 km away from intersection point.

Car b is traveling west at 80km/hr and 0.4 km away from the intersection point.

The time it will take to get to intersection point by those two cars is how fast it is changing.

For car A

Time = distance/speed

Time = 0.3/90

Time = 3.333*10^-3

Time = 3.333*10^-3 hrs

Converting to seconds

(3.333*10^-3)*360= 1.199998

Approximately 1.2 seconds

For car B

Time = distance/time

Time= 0.4/80

Time = 5*10^-3

Time= 5*10^-3 hrs

Converting to seconds

(5*10^-3)*360= 1.8 seconds

Comparing the two times,

Car A is 1.8-1.2= 0.6 times faster than car B

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2