An object carries a charge of -6.1 µC, while another carries a charge of -2.0 µC. How many electrons must be transferred from the first to the second object so that both objects have the same charge? Number of electrons

2.05µC

Explanation:

First object carries a charge of -6.1µC Second object carries a charge of -2.0 µC.

To make the charges same, divide the difference between both charges by 2

i.e - 6.1µC - (-2.0µC)

= -6.1µC + 2.0µC

= -4.1µC

Then, divide -4.1µC by 2

i.e (-4.1µC) /2

= -2.05µC

Now, transfer -2.05µC from first object to second object

i.e (-6.1µC - (-2.05µC))

= - 6.1µC + 2.05µC

= - 4.05µC

Thus, the second object becomes

(-2.0µC + (-2.05µC))

= -2.0µC -2.05µC

= - 4.05µC (note that the charges on first and second objects are now the same)

Thus, 2.05µC of electrons must be transferred from the first to the second object so that both objects have the same charge