1. A0_50 kg football is thrown with a velocity of 15 m/s to the right. A sta-
tionary rocciver catches the ball and brings it to rest in 0.020 s. What is
the force exerted on the receiver?

375 Newton

Explanation:

Initial velocity = 15 m/s

Final velocity = 0 m/s

Mass of football = 0.50kg

Time taken = 0.020Seconds

Force = (Change in momentum / Time taken)

Since, change in momentum = Mass (final velocity - initial velocity)

Change in momentum = 0.50 x (0 - 15)

= 0.50 (-15)

= - 7.5kgm/s

Then, put - 7.5kgm/s in the equation of force

i.e Force = (Change in momentum / Time taken)

Force = (- 7.5kgm/s / 0.020 Seconds)

Force = 375 Newton (note that the negative sign does not affect the value of force)

Thus, 375 Newton of force was exerted on the receiver

not too sure thinking it will always be directed towards the centre of the earth. could be wrong not sure

the entire statement is true and correct.  

there's no diagram, nothing is illustrated, and no question is asked.