Liquid chlorobenzene goes through a process where there is negligible heat flow and no work done on the surroundings. initially it is at 330 k and 3,500 kpa. at the end of the process the final pressure is 2,000kpa. estimate the temperature change and the entropy change of chlorobenzene.

The change in temperature is -141.428K

The entropy change is -60.75J/mole K Kg

Explanation:

Given that,

Initial Temperature, T₁ = 330k

Initial Pressure, P₁ = 3500kpa

Final pressure, P₂ = 2000kpa

Since the work done on the surrounding is zero

hence, the change in volume of the system will be zero and the process will be constant

Calculate the Temperature of the system

Substitute the value in the above equation

Calculate the change in temperature

ΔT = T₂ - T₁

     = 188.57K - 330K

      = -141.428K

The change in temperature is -141.428K

Expression of change in entropy

ds is the entropy change

equation for

Substitute for dQ in the expression of change in entropy and integrate

substitute the values

The entropy change is -60.75J/mole K Kg

continuous conducting path for current, power supply

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.