How much heat energy must be added to 52kg Of water at 68°F to raise the temperature to 212°F? The specific heat capacity for water is 4.186×10 to the third power J/kg times degrees Celsius

The amount of energy added to rise the temperature Q = 17413.76 KJ

Explanation:

Mass of water = 52 kg

Initial temperature = 68 °F = 20° c

Final temperature = 212 °F = 100° c

Specific heat of water  

Now heat transfer Q = m × C × (  - )

⇒ Q = 52 × 4.186 × ( 100 - 20 )

⇒ Q = 17413.76 KJ

This is the amount of energy added to rise the temperature.

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27

answer and explanation;