A long nonconducting cylinder (radius = 12 cm) has a charge of uniform density (5.0 nC/m3) distributed throughout its volume. Determine the magnitude of the electric field 15 cm from the axis of the cylinder. Group of answer choices 12 N/C 20 N/C 27 N/C 16 N/C 54 N/C

The magnitude of the electric field is 27 N/C

Explanation:

Given;

radius of the cylinder, r = 12 cm = 0.12 m

uniform density, λ = 5.0 nC/m³

distance from the axis, R = 15 cm = 0.15 m

Volume of a cylinder, V = πr²h

charge on the cylinder, q = V λ = πr²hλ = π (0.12)²h x 5.0 = 0.072πh nC

from Gauss law;

Substitute in the value of q into this equation and solve for E

q =  0.072πh nC

Therefore, the magnitude of the electric field is 27 N/C

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6