A 100-kg box is sitting on a 10 degree incline with a coefficient of friction of 0.5. At what angle must the incline be raised to start sliding on the box?

26.56°

Explanation:

μ= 0.5

F = ?

N =?

Fs = μN

Fs = force acting due to friction (on an inclined plane)

N = normal force.

μ= coefficient of friction

μ= tanΘ

μ= tan 0.5

Θ = tan⁻¹ 0.5

Θ = 26.56°

The angle in which is required for the box to start moving across the inclined plane is 26.56°

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

c) power lifting, will be your answer.

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