Point charges of 28.0 µC and 42.0 µC are placed 0.500 m apart. (a) At what point (in m) along the line connecting them is the electric field zero? m (from the smaller charge) (b) What is the magnitude (in N/C) and direction of the electric field halfway between them? magnitude N/C direction

The electric field strength is directly proportional to the force exerted on chareges. The electric field will be zero only at the point charges not in between them.

Where,

- electric field strength

- force  =

- charge

So, for the smaller charge,  

Where,

- distance

For E to be zero,

Therefore, the electric field will be zero only at the point charges not in between them.

Learn more about Electric Field Strength:

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a) electric field will be zero at zero meters apart

b) for smaller charge q, E = 6.048X10^6N/m towards away from the charge,

for bigger charge Q, E = 4.032X10^6N/m

Explanation:

Detailed explanation and calculation is shown in the image below.

i'm thinking more like energy

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.