A student attaches a block to a vertical spring so that the block-spring system will oscillate if the block-spring system is released from rest at a vertical position that is not the system’s equilibrium position. The system oscillates near Earth’s surface. The system is then taken to the Moon’s surface, where the gravitational field strength is nearly 16 that of the gravitational field strength near Earth's surface. Which of the following claims is correct about the period of oscillation for the system?

The arrangement of the planets around the sun is called the solar system and it revolves around the sun in an elliptical pathway. The planets revolve around in a circular motion with the help of centripetal force.

The correct answer is , the solution is as follows:-

According to the law, the time taken by the planet to move around the sun will remain the same.

Hence, the solution of the question is as follows:-

The time period required for the oscillation is . In this equation, the M stands for the mass of an object, k stands for spring constant, and T stands for time.

The time period is independent of the:-

At the maximum, position,

Hence, the Time period of the motion will remain the same while the amplitude of the motion will change.

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Time period of the motion will remain the same while the amplitude of the motion will change

Explanation:

As we know that time period of oscillation of spring block system is given as

now we know that

M = mass of the object

k = spring constant

So here we know that the time period is independent of the gravity

while the maximum displacement of the spring from its mean position will depends on the gravity as

so we can say that

Time period of the motion will remain the same while the amplitude of the motion will change

need to see circuit to get time constant

false.

explanation:

this statement is false. after falling for 5 seconds, its speed will not be 100 m/s.