Physics, 26.03.2020 05:42 101EXPERIENCE

A student attaches a block to a vertical spring so that the block-spring system will oscillate if the block-spring system is released from rest at a vertical position that is not the system’s equilibrium position. The system oscillates near Earth’s surface. The system is then taken to the Moon’s surface, where the gravitational field strength is nearly 16 that of the gravitational field strength near Earth's surface. Which of the following claims is correct about the period of oscillation for the system?

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The arrangement of the planets around the sun is called the solar system and it revolves around the sun in an elliptical pathway. The planets revolve around in a circular motion with the help of centripetal force.

The correct answer is $x = \frac{mg}{k}$ , the solution is as follows:-

According to the law, the time taken by the planet to move around the sun will remain the same.

Hence, the solution of the question is as follows:-

The time period required for the oscillation is $T = 2\pi \sqrt{\frac{M}{k}}$ . In this equation, the M stands for the mass of an object, k stands for spring constant, and T stands for time.

The time period is independent of the:-

Gravity

At the maximum, position,

mg = kx

$x = \frac{mg}{k}$

Hence, the Time period of the motion will remain the same while the amplitude of the motion will change.

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Answer from: boopiee2349

Time period of the motion will remain the same while the amplitude of the motion will change

Explanation:

As we know that time period of oscillation of spring block system is given as

$T= 2\pi\sqrt{\frac{M}{k}}$

now we know that

M = mass of the object

k = spring constant

So here we know that the time period is independent of the gravity

while the maximum displacement of the spring from its mean position will depends on the gravity as

mg = kx

$x = \frac{mg}{k}$

so we can say that

Time period of the motion will remain the same while the amplitude of the motion will change

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

Answer from: Quest

your answer is, orbit around the nucleus

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A student attaches a block to a vertical spring so that the block-spring system will oscillate if th...