A flowerpot falls off a second story windowsill and hits the sidewalk 1.5 s later with a velocity of 14.7 m/s find the average acceleration of the flowerpot

The average acceleration of the flowerpot will be .

Explanation:

The average acceleration is equal to change in velocity divided by change in time in given interval.

Here v is the final velocity and u is the initial velocity.

Given v = 14.7 m/s, u = 0 (as flowerpot falls off a second story windowsill) and .

Substitute the given values, we get

Thus, the average acceleration of the flowerpot will be .

hope it

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west