A pair of parallel conducting rails that are 12 cm apart lies at right angles to a uniform magnetic field of 0.8 T directed into the page. A 15-ohm resistor is connected across the rails. A conducting bar is moved to the right at 2m/s across the rails.
1) What is the current in the resistor? (Express your answer to two significant figures.)
2) What is the magnetic force on the bar due to the induced current? (Express your answer to two significant figures.)

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Ithink the answer is d