Objects 1 and 2 attract each other with a electrostatic force
of 36.0 units. If the charge of Object 1 is halved AND the
charge of object 2 is tripled, then the new electrostatic force
will be units.

54.0 units

Explanation:

The electrostatic force between two charged particles is given by the equation:

where

k is the Coulomb constant

are the charges of the two particles

r is the separation between the particles

The direction of the force is:

- Repulsive if the two charges have same sign (++ or --)

- Attractive if the two charges have opposite sign (+-)

In  this problem, the initial force is

F = 36.0 units

when we have charges and distance .

Later:

- Charge of object 1 is halved, so

- Charge of object 2 is tripled, so

So, the new electrostatic force will be:

And using F = 36.0, we find