A meter stick whose mass is 260 grams lies on ice. You pull at one end of the meter stick, at right angles to the stick, with a force 6 newtons. The ensuing motion of the meter stick is quite complicated, but what are the initial magnitude and direction of the rate of change of the momentum of the stick, , when you first apply the force?

a = d p / dt = 23 m / s²,   The direction is the direction of the force

Explanation:

Newton's second law can be written in the form

             F = dp / dt

How the body is initially at rest

           F = m a

           a = F /m

           a = 6 /0.260

           a = 23 m / s²

           a = d p / dt = 23 m / s²

The direction is the direction of the force

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s