Umar has two copper pans, each containing 500cm3 of water. Pan A has a mass of 750g and pan B has a mass of 1.5kg. Which pan will require the least energy to heat the water to 100°C?

The pan that will require the least energy to heat the water to 100°C is pan A.

The given parameters;

The total energy required to raise the temperature of the water from the initial temperature to final temperature is calculated as follows;

where;

m is the mass of each pan

The pan with more mass will require more energy while the pan with least mass will require less energy.

Thus, the pan that will require the least energy to heat the water to 100°C is pan A.

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heat required in pan B is more than pan A

Explanation:

Heat required to raise the temperature of the substance is given by the formula

now we know that both pan contains same volume of water while the mass of pan is different

So here heat required to raise the temperature of water in Pan A is given as

Now similarly for other pan we have

So here by comparing the two equations we can say that heat required in pan B is more than pan A

ill do it for 100, also this isnt 80 its 40