A transverse wave is traveling on a string. The displacement y of a particle from its equilibrium position is given by y = (0.021 m)sin(29t - 2x). Note that the phase angle (29t - 2.0x) is in radians, t is in seconds, and x is in meters. The linear density of the string is 1.80 10-2 kg/m. What is the tension in the string?

3.7845 N

Explanation: The wave equation is given by

y = 0.021 sin (29t - 2x)

By comparing this to the general equation of a wave, we have that

y = A sin (ωt - kx)

Where ω = angular frequency.

After comparing, we see that

A = 0.021m, ωt = 29t and - 2x = - kx

Hence ω = 29 rad/s and k = 2.

The velocity of a wave is in relationship with angular frequency and wave number is given as

ω = kv

Where k = wave number

By substituting the parameters, we have that

29 = 2v

v = 29/2 = 14.5 m/s.

The velocity of wave in a spring is calculated using the formulae below.

v = √(T/u)

Where v = linear velocity = 14.5 m/s

T = tension =?

u = linear density = 1.80×10^-2 kg/m

By substituting the parameters, we have that

14.5 = √(T/ 1.80×10^-2)

By squaring both sides, we have that

14.5² = T/ 1.80×10^-2

T = 14.5² × 1.80×10^-2

T = 210.25 × 1.80×10^-2

T = 3.7845 N

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.

i think the answer is a, hope this : )