An instrument used a battery that provides 500 j of energy for 1200 seconds. what is the power of the instrument?

0.42watts

Explanation:

Energy of the battery = 500 J

Time = 1200 seconds

Power of the instrument = ?

Recall that power is the rate of energy expended in doing work. Thus, power is energy expended divided by time taken.

i.e Power = (energy/time)

Power = 500J/1200 seconds

Power = 0.416 watts (Round to the nearest hundredth which is 0.42 watts)

Thus, the power of the instrument is 0.42watts

snell's law

refractve index = sin incidence / sin refraction

inverse v=i*r

nice nice