1. A 1000 kg equipment lift travels up a 200 m shaft in 45 seconds. Assuming the speed is constant, what is the
average power?

43,555 W

Explanation:

Since the speed is constant, this means that the force applied to lift the equipment is equal to the weight of the equipment. So we can write:

where

m = 1000 kg is the mass

is the acceleration due to gravity

So,

Then the work done in lifting the equipment is:

where

d = 200 m is the displacement of the equpment

Substituting,

Finally, the power used to lift the equipment is the ratio between the work done and time taken:

where

t = 45 s is the time taken

Solving,

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s