A stunt woman attempts to swing from the roof of a m 24 high building to the bottom of an identical building using a m 24 rope, as shown in the figure above. She starts from rest with the rope horizontal, but the rope will break if the tension force in it is twice the weight of the woman. How high is the swinging woman above the ground level when the rope breaks? ( Hint: Use the law of conservation of energy and Newton’s Laws.)

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Height from ground is 8 m where string will break

Explanation:

Let the string makes some angle with the vertical after some instant of time

So here we have

now by energy conservation we have

For string break down we have

Now height from the ground is given as

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂