BRAINLIST AND 90 POINTS TO whoever CAN ANSWER these Questions

Sally sits and observes an ocean wave
A. she times waves and finds that it takes 32.8 s for 6.00 waves to pass by. What is the period of the wave?

B. What is the frequency of the wave?

C. she also notices that there is a distance of 1.82 m between crests. What is the wavelength of the wave?

D. finally, she records that from the highest point on a wave to the lowest point is a distance of .742m what is the amplitude of the wave?

E. Calculate the velocity of the wave

A. 5.5 s

B. 0.182 Hz

C. 1.82 m

D. 0.742 m

E.  0.33 m/s

Explanation:

A

Period is the time taken for a complete  wave to pass and since for this case we have 6 waves taking 32.8 s then the period will be equivalent to

Therefore, the period of the waves is approximately 5.5 seconds

B

Normally, frequency of a wave is equivalent to the reciprocal of its period, expressed as

where f is the frequency and T is the period in seconds. Since we already have period in part A above then substituting 5.5 s for T we obtain that

C

Wavelength is defined as the horizontal distance between two successive crests or troughs of a wave. The crests are the highest points of a wave and the troughs are the lowest points. Since we are given the distance between two crests already, we assume they are successive then the wavelength is equal to 1.82 m

D

Amplitude is the vertical distance between crest and trough to imply the distance between the highest and lowest point of a wave. In this case, that distance is provided as 0.742 m hence that is the amplitude

E

Velocity of a wave is given as the product of wavelength and frequency and expressed as v=fw where v is the velocity, f is the frequency and w is the wavelength. Since we are provided with frequency in part B as 0.182 Hz and the wavelength in part c as 1.82 m then the velocity will be v=0.182*1.82=0.33124 m/s and rounded off as 0.33 m/s