The tips of the blades of the Chinook helicopter lie on a circle of diameter of 18.29 meters. What is the airspeed v of the tip of the blades when they are rotating at 225 rpm? Answer in meters per second.

The linear speed is 215.46 m/s

Explanation:

Given:

Diameter, d = 18.29m

Radius, r = 18.29/ 2 = 9.145m

Angular speed, ω = 225 rpm

                        ω = 225 X π/30

                        ω = 23.56 rad/s

Linear speed, v = ?

We know

v = ωr

v = 23.56 X 9.145

v = 215.46 m/s

Therefore, linear speed is 215.46 m/s

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

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