A flat loop of wire consisting of a single turn of cross-sectional area 7.00 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 3.30 T in 0.99 s. What is the resulting induced current if the loop has a resistance of 1.80?

To solve this problem we must first find the potential on the body which is given as a product between the number of turns, the area and the variation of the magnetic field as a function of time. Once the potential is found, we will apply Ohm's Law with which we can find the induced current on the body. Our values are,

a) The magnitude of average induced emf is given by

Here N =1

b) The magnitude of the induced current is

Here Resistance is

Therefore the induced current is 0.00108A

the components of a vector are the parts of the vectors that are to each other.

b perpendicular