A 0.12-kg ball is moving at 6 m/s when it is hit by a bat, causing it to reverse direction and have a speed of 14 m/s. What is the magnitude of the change in the momentum of the ball

2.4 kg m/s

Explanation:

For change in momentum we have to find out initial and final momentum ,

So , change in momentum = final momentum - initial momentum

As momentum is vector so we have to take the direction also

Final momentum = 0.12 kg * 14 m/s = 1.68 kg m/s

Initial momentum = - 0.12 kg * 6 m/s = - 0.72 kg m/s

(Negative sign is due to change in direction)

So , change in momentum = 1.68kg m/s - ( - 0.72 kg m/s)

    = (1.68 + 0.72)kg m/s

   = 2.4 kg m/s