Light with a wavelength of (465 A) nm is incident on a metal surface with a work function of (1.25 (0.1)(B)) eV. Find the maximum kinetic energy of the emitted photoelectrons. Give your answer in eV and with 3 significant figures.

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Iwannasay c is the most accurate