• Light that has a 650-nm wavelength is incident upon two narrow slits that are separated by 0.500 mm. An interference pattern from the slits is projected onto a screen that is 3.00 m away. (a) What is the separation distance on the screen of the first bright fringe from the central bright fringe? (b) What is the separation distance on the screen of the second dark fringe from the central bright fringe?

(a) 3.9 mm

(b) 5.85 mm

Explanation:

Given that:

d = 0.500 mm, we need to convert this to meters so, d = 5.0 × m

lambda = 650 nm, this has to be converted to meters too so,

lambda = 6.5 × m and L = 3.00 m

(the symbol for lambda is not available so I'm just using the worded form)

(a) the general formula for finding the interference pattern is

dsin(theta) = nlambda

where sin(theta) = since the angle is not provided and n = 1 here since it refers to first bright fringe

(5.0 × )() = (1)(6.5 × )

= [(3)(6.5 × )] ÷ (5.0 × )

= 0.0039 m = 3.9 mm

(b) for the dark fringe, the formula will now be

dsin(theta) = (n-0.5)lambda

(5.0 × )() = (2-0.5)(6.5 × )

= [(3)(1.5)(6.5 × )] ÷ (5.0 × )

= 0.00585 m = 5.85 mm

Hope that answers the question. Have a great day!

f=ma newton

f=100x2.5=250n

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

hope this ! this is not copied! search it up, it's free of plagiarism!