A pilot can withstand an acceleration of up to 9g, which is about 88 m/s2, before blacking out. What is the acceleration experienced by a pilot flying in a circle of constant radius at a constant speed of 495 m / s if the radius of the circle is 1950 m

a = 125. 65 m/s²

Explanation:

The pilot is flying in a circle of constant radius at a constant speed .Since the motion is a circular motion we use the following formula

The angular acceleration a= ω²r = v²/r

ω = angular velocity

acceleration = v²/r

where

a = centripetal acceleration

a = ?

v = 495 m/s

r = 1950 m

a = v²/r

a = 495²/1950

a = 245025/1950

a = 125.653846154

a = 125. 65 m/s²

Acceleration, a_c= 125.65 m/s²

Explanation:

The motion in the question is a circular motion and thus, the centripetal acceleration is given by;

a_c = v²/r

Where;

a_c = centripetal acceleration

v = velocity

r = radius

From the question,

v = 495 m/s

r = 1950 m

Thus, plugging in this values, we have;

a_c = v²/r

a_c = 495²/1950

a_c = 245025/1950

a_c = 125.6538 ≈ 125.65 m/s²

explanation:

the masses of the objects and the distance between them

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