A small current element carrying a current of I = 1.00 A is placed at the origin given by d → l = 4.00 m m ^ j Find the magnetic field, d → B , at the locations specified. Enter the correct magnitude and select the direction from the list. If the direction is negative, indicate this by entering the magnitude as a negative number. What is the magnitude and direction of d → B on the x ‑axis at x = 2.50 m ? magnitude: T Direction: ^ k ^ j ^ i What is the magnitude and direction of d → B on the z ‑axis at z = 5.00 m ?

the magnitude and direction of d → B on the x ‑axis at x = 2.50 m is -6.4 × 10⁻¹¹T(Along z direction)

the magnitude and direction of d → B on the z ‑axis at z = 5.00 m is 1.6 × 10⁻¹¹T(Along x direction)

Explanation:

Use Biot, Savart, the magnetic field

Given that,

i = 1.00A

d → l = 4.00 m m ^ j

r = 2.5m

Displacement vector is

 =2.5m

on the axis of x at x = 2.5

r = 2.5m

And unit vector

Therefore, the magnetic field is as follow

(Along z direction)

B)r = 5.00m

Displacement vector is

 =5.00m

on the axis of x at x = 5.0

r = 5.00m

And unit vector

Therefore, the magnetic field is as follow

(Along x direction)

1 the 4 is sig

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle