You carry a 7.0 kg bag of groceries above the ground at constant velocity across a room. How much work do you do on the bag in the process (The force you apply is vertically straight up.)?

Zero.

Explanation:

As it has been said in the question that bag is carried horizontally at constant velocity by lifting  it with an upward force.

So, according to the question the angle between the force and displacement here is 90°.

According to the definition,

Work is the dot product of the force applied to the object and the displacement produced in the object.

So,

Work = = θ

Since the angle is 90°, the value of cosθ in the above equation will be zero and thus the value of net work done will also be zero.

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