A length of copper wire has a resistance 29 Ω. The wire is cut into three pieces of equal length, which are then connected as parallel lengths between points A and B. What resistance will this new "wire" of length L0 3 have between points A and B? Answer in units of Ω.

3.222 ohms

Explanation:

If the total wire had a resistance of 29 ohms, when cut in three, each piece will have a resistance of 9.666 ohms.

As these three pieces (R1, R2 and R3) are now connected in parallel, the equivalent resistance R can be calculated using this equation:

1/R = 1/R1 + 1/R2 + 1/R3

1/R = 1/9.666 + 1/9.666 + 1/9.666

1/R = 3/9.666

R = 9.666/3 = 3.222 ohms

The resistance between A and B will be 3.222 ohms

find the sum of the two horizontal vectors and the sum of the two vertical vectors

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