Two automobiles traveling at right angles to each other collide and stick together. Car A has a mass of 1200 kg and had a speed of 25 m/s before the collision. Car B has a mass of 1600 kg. The skid marks show that, immediately after the collision, the wreckage was moving in a direction making an angle of 40° with the original direction of car A. What was the speed of car B before the collision, assuming that any other unbalanced forces are negligible?

Explanation:

We can use the conservation of momentum. The initial momentum is equal to the final momentum:

x-coordinate

(1)

y-coordinate

(2)

We can divide equations (2) and (1):

I hope it helps you!

The speed of car b before collision is 15.72 m/s

Explanation:

Given that,

Mass of car a= 1200 kg

Speed = 25 m/s

Mass of car b = 1600 kg

moving in a direction making an angle of 40°

We need to calculate the speed of car b before the collision

Using conservation of momentum

Horizontal momentum,

substitute the value into the formula

Vertical momentum,

substitute the value into the formula

Thus, The speed of car b before collision is 15.72 m/s

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