Light of wavelength 630 nm falls on two slits and produces an interference pattern in which the third-order bright red fringe is 35 mm from the central fringe on a screen 2.8 m away. Part A What is the separation of the two slits?

The separation of the two slits is = 1.5 × m

Explanation:

Wave length = 630 nm = 0.63 mm

x = 35 mm

l = 2.8 m

Order of fringes (m) = 3

We know that the separation of the two slits is given by

Put all the values in above formula we get

d = 1.5 × m

Therefore the separation of the two slits is = 1.5 × m

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.