A 95-N force exerted at the end of a 0.32-m long torque wrench produces a torque of 15 N • m. What is the angle (less than 90°) between the wrench handle and the direction of the applied force?

Angle between force exerted and handle of the wrench is 29.56 degree

Explanation:

We have given force exerted at the end of the wrench  F = 95 N m

Length of the wrench d = 0.32 m

Torque is given as

Let the angle between wrench handle and force exerted is

Torque is equal to

So angle between force exerted and handle of the wrench is 29.56 degree

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures

the ima (higher than 1m) will be greater than the ima with the height of 1m.