A particle carrying a charge of +e travels in a circular path in a uniform magnetic field. If instead the particle carried a charge of +2e, the radius of the circular path would have been

A. 2R
B. 4R
C. 8R
D. R/2
E. R/4

The radius of the circular path =

Explanation:

The force on a charged particle s given by

F = q v B ------ (1)

This force is equal to the centripetal force acting on the particle because the particle travels in circular path.

The centripetal force

----- (2)

Equation (1) = Equation (2)

q v B =

From the above relation we are seeing that radius of the circular path is inversely proportional to the charge (q).

So when the charge doubles the radius of  circular path is halved.

So  the radius of the circular path =

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

the answer is kevlar