A soccer ball of mass m1 = 0.51 kg is initially at rest. Another soccer ball of m2 = 0.528 kg is kicked at the first ball such that the system has an initial momentum vector of Pi = Pxi + Pyj where Px = 0.88 kg m/s and Py = 0.85 kg m/s. Randomized Variables m1 = 0.51 kg m2 = 0.528 kg Px = 0.88 kg m/s Py = 0.85 kg m/s show answer Correct Answer 33% Part (a) Write an expression for the initial velocity v2i for m2 in terms of the mass and the initial momentum. v2i = ( Px i + Py j )/m2 ✔ Correct! show answer Incorrect Answer 33% Part (b) Write an expression for the final velocity v1f for m1, if v2f = v2fj. v1f = ( √( Px2 + Py2 ) - m2 v2f )/m1 ✘ Attempts Remain show answer Incorrect Answer 33% Part (c) Numerically what is the magnitude of the final velocity v1f for m1, if v2f = 0.5j m/s? |v1f| = 1.88| sin() cos() tan() cotan() asin() acos() atan() acotan() sinh() cosh() tanh() cotanh() Degrees Radians π ( ) 7 8 9 HOME E ↑^ ^↓ 4 5 6 ← / * 1 2 3 → + - 0 . END √() BACKSPACE DEL CLEAR Grade Summary Deductions 4% Potential 96% Submissions Attempts remaining: 2 (4% per attempt) detailed view 1 4% Hints: 4% deduction per hint. Hints remaining: 2 Feedback: 5% deduction per feedback.