At a certain time a particle had a speed of 46 m/s in the positive x direction, and 9.1 s later its speed was 67 m/s in the opposite direction. What was the average acceleration of the particle during this 9.1 s interval

The average acceleration of the particle during this 9.1 s interval is  .

Explanation:

The expression for the average acceleration of the particle is as follows;

Here, is the average acceleration, v is the final speed, u is the initial speed, t is the initial time and t' is the final time.

It is given in the problem that at a certain time a particle had a speed of 46 m/s in the positive x-direction, and 9.1 s later its speed was 67 m/s in the opposite direction.

Put , , t= 0 and t'=9.1 s in the above expression.

Therefore, the average acceleration of the particle during this 9.1 s interval is  .

i don’t know what the answer is i wish i

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.