Many gases are shipped in high-pressure containers. consider a steel tank whose volume is 55.0 gallons and which contains o2 gas at a pressure of 16,500 kpa at 23 degrees c.. what is the mass of o2 in the tank in g? . what volume would the gas occupy at stp in liters? . at what temperature would the pressure in tank equal 1.55 atm? . what would be the pressure of the gas, in kpa, if it were transferred to a container at 24 degrees c, whose volume is 55.0 l ?

We are given with conditions on temperature, pressure and volume of gas. In this problem, we apply ideal gas law PV = nRT to solve what are asked.

1. PV = nRT ; n = m/MM
    16.5 x10^6 Pa * 0.003785 m3= n * 8.314 Pa m^3/ mol K * (23+273) K 
    n = 25.38 mol; mass = 812.08 grams. 
2. V at STP is 22.4 L/mol
3. PV = nRT = 1.5 atm *  0.003785 *1000 L = 25.38 mol * 0.0821 L atm/mol K * T ; T = 2.72 K
4. P * 55 m3/1000 = 25.38 mol * 8.314 Pa m^3/ mol K * (24+273) K
  P = 1139. 45 kPa

If an object is moving or in motion

The earths atmosphere is made up of nitrogen and oxygensolids turning into gases is called sublimation.