A 2.0-cm length of wire centered on the origin carries a 20-A current directed in the positive y direction. Determine the magnetic field at the point x = 5.0 m on the x-axis.

field strength = 8x10^-8T

Explanation:

At a distance r from a long current carrying conductor of current I,

B = uL/2¶r

Where u = 4¶x10^-7 H/m = permeability of free space.

r = 5m

I = 20A

B = (4¶x10^-7 x 20)/2¶x5

B = 8x10^-8T

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

f=ma newton

f=100x2.5=250n