A thundercloud has an electric charge of 43.2 C near the top of the cloud and -38.7 C near the bottom of the cloud. The magnitude of the electric force between these two charges is 3.95 x 106 N. What is the average separation between these charges? (kc = 8.99 ×109 N • m2 / C2)

1950.65m

Explanation:

Coulomb's law states that the force F of attraction between two charges q1 and q2 is directly proportional to the product of the charges and inversely proportional to the square of the distance d between them. Mathematically;

|F| = k |q1||q2| /r²

Given |q1| = |43.2| C = 43.2C

|q2| = |-38.7|C = 38.7C

F = 3.95 x 106 N

d = ?

k is the coloumbs constant = 8.99 ×109 Nm2 / C2

Substituting this values in the formula to get distance d we have;

3.95x10^6= 8.99×10^9×43.2×38.7/d²

3.95x10^6d² = 15,029,841,600,000

d² =15,029,841,600,000/3,950,000

d² = 3,805,023.189

d = √3,805,023.189

d = 1950.65m

Average separation between the charges is 1950.65m

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.