0.01 kg of 4.0°C water is heated until its temperature is 37°C. If the specific heat of water is 4186J/kg°C, calculate the amount of heat energy needed to cause this
rise in temperature.
(Round to 2 Decimal Places)

1381.38 joules

Explanation:

The amount of heat energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = ?

Mass of water = 0.01kg

C = 4186J/kg°C

Φ = (Final temperature - Initial temperature)

= 37°C - 4.0°C = 33.0°C

Then, Q = MCΦ

Q = 0.01kg x 4186J/kg°C x 33.0°C

Q = 1381.38 J

Thus, 1381.38 Joules of heat energy is needed to cause this rise in temperature.

reserve is the answer