Ammonia gas occupies a volume of 0.450 L at a pressure of 96 kPa. What
volume will it occupy at standard pressure (101.3 kPa)? *

0.426 L

Explanation:

Boyles law is expressed as p1v1=p2v2 where

P1 is first pressure, v1 is first volume

P2 is second pressure, v2 is second volume.

Given information

P1=96 kPa, v1=0.45 l

P2=101.3 kpa

Unknown is v2

Making v2 the subject from Boyle's law

Substituting the given values then

Therefore, the volume is approximately 0.426 L

massxgravity x heght=weightxheight= pe

4900=490xh

h=10