A 4.6-mm-diameter proton beam carries a total current of 1.8 mA . The current density in the proton beam, which increases with distance from the center, is given by J=Jedge(r/R) , where R is the radius of the beam and Jedge is the current density at the edge. Part A How many protons per second are delivered by this proton beam? Express your answer using two significant figures.

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

this is a good question! i'll do some research and come back when i have the answer!

measure their densities same density, same sub