You push your physics book 1.50 m along a horizontal tabletop with a horizontal push of 2.40 N while the opposing force of friction is 0.600 N. How much work does each of the following forces do on the book: (a) your 2.40-N push, (b) the friction force, (c) the normal force from the tabletop, and (d) gravity? (e) What is the net work done on the book?

a) 3.6 J

b) 0.9 J

c) 0 J

d) 0 J

e) 2.7 J

Explanation:

Work = force F x diaplament in direction of force d

Given that,

Displacement in direction of push force d = 1.5 N

Push force = 2.4 N

Friction = 0.6 N

a) work done by push force = 2.4 x 1.5 = 3.6 J

b) word done by friction = -0.6 x 15 = -0.9 J (minus sign shows the work is opposite that done by the push force)

c) work done by normal force from table top ( force acting upwards to oppose gravity) = 0 J since there is no vertical displacement

d) work done by gravity (doward force) = 0 J since there is no vertical displacement

e) net work done on book = 3.6 J + (-0.9J) + 0 J + 0 J = 2.7 J

that tool is called an altimeter which measures your altitude which can be used to tell which atmosphere you are currently in, including the stratosphere.

hope this ! : )