A 1000 kg car traveling 20 m/s east experiences an impulse of 2000 Ns west. What is the final velocity of the car after the impulse has been applied?

V=18 m/s

Explanation:

Impulse is represented by Δp. It can be expanded such as: Δp = m(v-u) , where m is mass, v is final velocity, and u is initial velocity. (sorry ib physics things)

You can substitute your given values into the equation.

Δp = -2000 (i kept this as negative since it is going the opposite direction to your initial velocity)

m = 1000 kg

u = 20 m/s

1.  -2000 = 1000(v-20)  --> -2000/1000

2.   -2 = v-20 --> -2 + 20

3.  v = 18 m/s

You can always double check your answer by substituting it back into the original equation to make sure the Δp = -2000

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach