Light passes through a single slit of width 8.32x10^-5 m. The first (m=1) diffraction minimum occurs at an angle of 0.347. What is the wavelength of the light in nanometers?
(Hint: The answer will be between 400 and 700 nm.)

Explanation:

theta = m wavelength/ silt width

gives angular position of minimas where m= 1,2,3...

As

0.347° = pi/180 × 0.347 rad = 0.006 rad

using above formula

0.006= 1 × wavelength/ 8.32 × 10^-5 m

wavelength = 0.006× 8.32 × 10^ -5 m

= 0.04992× 10^ -9 m

= 499× 10^ -9m

=499 nm

which is almost 500 nm

answer: i pick a

explanation:

your answer is c! hope this : )