Two automobiles are equipped with the same single-frequency horn. When one is at rest and the other is moving toward the first at 10 m/s, the driver at rest hears a beat frequency of 5.0 Hz.
What is the frequency the horns emit?

f = 4.85 Hz

Explanation:

This question is an example of the Doppler's effect

We are given that ;

The source velocity; v_s = 10 m/s

The apparent frequency f'= 5 Hz

We will also need the speed of sound in air and it has a constant value of 340 m/s. Thus, v = 340 m/s

Now, the true frequency is given by the formula;

f = [(v - v_s)/v]•f'

Where;

v is speed of sound in air

v_s is speed of source

f' is apparent frequency

Thus, plugging in the relevant values, we have;

f = [(340 - 10)/340]•5

f = (330/340)•5

f = 4.85 Hz

low freq = 100 mhz

low wavelength =101.7m

length = 3x10^8/freq

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever