2. A force of 24x10² N exists between a positive charge of 8x10-5C and a positive charge of 3x10C.
What distance separates the charges?

94.9 metres

Explanation:

Given that,

Force between the two charges (F) = 24x10² N

Negative charge (q1) = 8x10-5C

Positive charge (q2) = 3x10C

Distance between charges (r) = ?

Apply the formula for

F= (kq1q2) / r²

Recall that k is Coulomb's constant with a value of 9 × 10^9 Nm2C−2

Then,

24x10² N = (9 × 10^9 Nm2C−2 x 8x10-5C x 3x10C) / r²

24x10² N = (2.16 x 10^7) / r²

r² = (2.16 x 10^7 / 24x10² N)

r² = 9000

To get the value of r, find the square root

r = √9000

r = 94.868m (rounded to the nearest tenth as 94.9m)

Thus, a distance of 94.9 metres separates the charges.

double the distance = divide strength by 4

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