High-speed stroboscopic photographs show that the head of a 260-g golf club is traveling at 51 m/s just before it strikes a 46-g golf ball at rest on a tee. After the collision, the club head travels (in the same direction) at 38 m/s. Find the speed of the golf ball just after impact.

The concept necessary to solve this problem is linked to the conservation of momentum, for which it is established that the initial momentum must be equal to the final momentum. Therefore, the product between the initial speeds times the mass will be equal to the product of the final speeds times the mass, therefore we have that our values are:

After collision we have,

From conservation of linear momentum,

Rearranging to find the velocity 2,

Replacing,

Therefore the speed of the golf ball just after impact is 73.47m/s

f=ma newton's second law 7x8=56n

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.